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Чонин88
@Чонин88
July 2022
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ПОМОГИТЕ ОЧЕНЬ СРОЧНО
решите в целых числах уравнение:
(х+у+1)(х-1)=3
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IrkaShevko
Verified answer
Всего 4 случая 3=1*3=3*1=(-1)*(-3)=(-3)*(-1)
1) x - 1 = 1 => x = 2
x + y+ 1 = 3
3 + y = 3 => y = 0
(2; 0)
2) x - 1 = 3 => x = 4
x + y + 1 = 1
5 + y = 1 => y = -4
(4; -4)
3) x - 1 = -1 => x=0
x + y + 1 = -3
y+1=-3
y=-4
(0; -4)
4) x - 1 = -3 => x = -2
x + y + 1 = -1
-1 + y = -1
y = 0
(-2; 0)
Ответ: (2; 0), (4; -4), (0; -4), (-2; 0)
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Answers & Comments
Verified answer
Всего 4 случая 3=1*3=3*1=(-1)*(-3)=(-3)*(-1)1) x - 1 = 1 => x = 2
x + y+ 1 = 3
3 + y = 3 => y = 0
(2; 0)
2) x - 1 = 3 => x = 4
x + y + 1 = 1
5 + y = 1 => y = -4
(4; -4)
3) x - 1 = -1 => x=0
x + y + 1 = -3
y+1=-3
y=-4
(0; -4)
4) x - 1 = -3 => x = -2
x + y + 1 = -1
-1 + y = -1
y = 0
(-2; 0)
Ответ: (2; 0), (4; -4), (0; -4), (-2; 0)