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Julia0fox
@Julia0fox
July 2022
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Помогите, пожалуйста, решить уравнения.СРОЧНО!
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kmike21
Verified answer
5) (1-sinx)ctgx=cosx
(1-sinx)cosx/sinx=cosx
(1-sinx)cosx=cosx sinx
I. cosx=0 x=π/2+πk
II. 1-sinx=sinx
2sinx=1
sinx=1/2
6)
x/2≠πk или x≠2πk/
1-cos²(x/2)+sin²(x/2)=2sin(x/2)
2sin²(x/2)=2sin(x/2)
sin²(x/2)=1
sin(x/2)=+-1
x/2=π/2+πk
x=π+2πk=(1+2k)π
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Answers & Comments
Verified answer
5) (1-sinx)ctgx=cosx(1-sinx)cosx/sinx=cosx
(1-sinx)cosx=cosx sinx
I. cosx=0 x=π/2+πk
II. 1-sinx=sinx
2sinx=1
sinx=1/2
6)
x/2≠πk или x≠2πk/
1-cos²(x/2)+sin²(x/2)=2sin(x/2)
2sin²(x/2)=2sin(x/2)
sin²(x/2)=1
sin(x/2)=+-1
x/2=π/2+πk
x=π+2πk=(1+2k)π