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Julia0fox
@Julia0fox
August 2022
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Решить уравнение (логарифмы)
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mikael2
Verified answer
2log₉x=2*1/2*log₃x log₃x=z
√(1+z) + √(4-z)=3 z>-1
x >1/3
4-z>0 z<4
x<3⁴=81
1+z+4-z +2√(1+z)(4-z)=9 √(1+z)(4-z) = 2
4+4z-z-z²-4=0 -z²+3z=0 z²-3z=z(z-3)=0
z=0 z=3
log₃x=0 log₃x=3
x=1 x=3³=27
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Answers & Comments
Verified answer
2log₉x=2*1/2*log₃x log₃x=z√(1+z) + √(4-z)=3 z>-1 x >1/3 4-z>0 z<4 x<3⁴=81
1+z+4-z +2√(1+z)(4-z)=9 √(1+z)(4-z) = 2
4+4z-z-z²-4=0 -z²+3z=0 z²-3z=z(z-3)=0
z=0 z=3
log₃x=0 log₃x=3
x=1 x=3³=27