Ответ:

1)

дано

V(H2) = 33.6 L

-----------------

m(CH4)- ?

C+2H2-->CH4

n(H2) = v/Vm = 33.6 / 22.4 = 1.5 mol

2n(H2) = n(CH4)

n(CH4) = 1.5 / 2 = 0.75 mol

M(CH4) = 16 g/mol

m(CH4) = n*M = 0.75* 16 = 12 g

ответ 12 г

2.

дано

m(ppa HCL) = 73 g

W(HCL) = 20 %

----------------------

V(H2)-?

m(HCL) = 73 * 20% / 100% = 14.6 g

Mg+2HCL-->MgCL2+H2

M(HCL) = 36.5 g/mol

n(HCL) = m/M = 14.6 / 36.5 = 0.4 mol

2n(HCL) = n(H2)

n(H2) = 0.4 / 2 = 0.2 mol

V(H2) = n*Vm = 0.2 * 22.4 = 4.48 L

ответ 4.48 л

Объяснение: