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Julia0fox
@Julia0fox
July 2022
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Пожалуйста, найти корни уравнения....спасибо
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kmike21
Verified answer
Sin(x-π/6)-√3/2=-√3
sin(x-π/6)=-√3/2
x₁-π/6=π/3+π и x₂-π/6=2π-π/3
x₁=π/3+π/6+π=π(3+1+6)/6=10π/6=5π/3
x₂=2π-π/3+π/6=π(12-2+1)/6=11π/6
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Answers & Comments
Verified answer
Sin(x-π/6)-√3/2=-√3sin(x-π/6)=-√3/2
x₁-π/6=π/3+π и x₂-π/6=2π-π/3
x₁=π/3+π/6+π=π(3+1+6)/6=10π/6=5π/3
x₂=2π-π/3+π/6=π(12-2+1)/6=11π/6