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alina44511
@alina44511
March 2022
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Пожалуйста помогите!!!!!!!!!! Найти экстремумы заданной функции!
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IrkaShevko
Verified answer
Dz/dx = 4x + 2y - 10 = 0 |*3
dz/dy = -6y + 2x + 16 = 0
12x + 6y - 30 = 0
2x - 6y + 16 = 0
14x = 14
x = 1
2y = 10 - 4x = 6
y = 3
(1; 3) -критическая точка
d²z/dx² = 4
d²z/dy² = -6
d²z/(dxdy) = 2
4 * (-6) - 4 = -28 < 0 - нет глобального экстремума
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Answers & Comments
Verified answer
Dz/dx = 4x + 2y - 10 = 0 |*3dz/dy = -6y + 2x + 16 = 0
12x + 6y - 30 = 0
2x - 6y + 16 = 0
14x = 14
x = 1
2y = 10 - 4x = 6
y = 3
(1; 3) -критическая точка
d²z/dx² = 4
d²z/dy² = -6
d²z/(dxdy) = 2
4 * (-6) - 4 = -28 < 0 - нет глобального экстремума