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Kamal1999
@Kamal1999
July 2022
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ПОЖАЛУЙСТА ПОМОГИТЕ НОМЕР 6
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sedinalana
Verified answer
1/2*(cos(3x-5x))=1/2(cos(x-7x)-cos(x+7x))
cos2x-cos8x=cos6x-cos8x
cos2x=cos6x
cos2x-cos6x=0
2sin4xsin2x=0
sin4x=0⇒4x=πn⇒x=πn/4,n∈z
sin2x=0⇒2x=πk⇒x=πk/2,k∈z
общее x=πn/4,n∈z
1 votes
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Kamal1999
А почему пn/4 общее?
sedinalana
Клавиша при нажатии в символах делает повтор,не проследила,конечно просто П
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Answers & Comments
Verified answer
1/2*(cos(3x-5x))=1/2(cos(x-7x)-cos(x+7x))cos2x-cos8x=cos6x-cos8x
cos2x=cos6x
cos2x-cos6x=0
2sin4xsin2x=0
sin4x=0⇒4x=πn⇒x=πn/4,n∈z
sin2x=0⇒2x=πk⇒x=πk/2,k∈z
общее x=πn/4,n∈z