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Tomkaya
@Tomkaya
July 2022
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MizoriesKun
Lg(x+11) -1/2lg(2x+7)=2-lg25
ОДЗ х+11>0 x>-11; 2x+7>0 x>-3,5
lg(x+11) - lg√(2x+7)=lg 100 - lg25
lg(x+11) / √(2x+7)=lg 100 /25
lg(x+11) / √(2x+7)=lg 4
(x+11) / √(2x+7)= 4
(x+11) = 4*√(2x+7)
(x+11)² = (4*√(2x+7))²
х²+22х+121=16*(2х+7)
х²+22х+121=32х+ 112
х²-10х+9=0
D=100-36=64
x₁=(10+8)/2=9
x₂=(10-8)/2=1
∑=9+1=10
1 votes
Thanks 1
Tomkaya
Благодарю!!
MizoriesKun
))
MizoriesKun
обнови страничку
Tomkaya
;)) ахах, теперь идеально)
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Answers & Comments
ОДЗ х+11>0 x>-11; 2x+7>0 x>-3,5
lg(x+11) - lg√(2x+7)=lg 100 - lg25
lg(x+11) / √(2x+7)=lg 100 /25
lg(x+11) / √(2x+7)=lg 4
(x+11) / √(2x+7)= 4
(x+11) = 4*√(2x+7)
(x+11)² = (4*√(2x+7))²
х²+22х+121=16*(2х+7)
х²+22х+121=32х+ 112
х²-10х+9=0
D=100-36=64
x₁=(10+8)/2=9
x₂=(10-8)/2=1
∑=9+1=10