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serega61356
@serega61356
April 2022
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решить уравнение ......................
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blake28929
Надеюсь что все понятно
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serega61356
Я уже сам решил
blake28929
Молодец
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[tex]cosx\ \textgreater \ 0\\- \frac{ \pi }{2} +2 \pi n\ \textless \ x\ \textless \ \frac{ \pi }{2} +2 \p \pi i n\\tg^2+tgx=0\\tgx(tgx+1)=0\\[tex]- \frac{7 \pi }{2} \leq- \frac{ \pi }{4} +2 \pi k \leq -2 \pi |+ \frac{ \pi }{4} \\- \frac{14\pi }{4} + \frac{\pi}{4} \leq2 \pi k \leq - \frac{8 \pi }{4} + \frac{ \pi }{4}\ |: 2\pi \\- \frac{13}{8} \leq k \leq - \frac{7}{8} , \ k=-1, \ x=-2 \pi [/tex][tex]- \frac{7 \pi }{2} \leq- \frac{ \pi }{4} +2 \pi k \leq -2 \pi |+ \frac{ \pi }{4} \\- \frac{14\pi }{4} + \frac{\pi}{4} \leq2 \pi k \leq - \frac{8 \pi }{4} + \frac{ \pi }{4}\ |: 2\pi \\- \frac{13}{8} \leq k \leq - \frac{7}{8} , \ k=-1, \ x=-2 \pi [/tex]tgx=0, \ x= \pi n, \ uchitivaya\ ODZ:\ x=2 \pi n\\tgx=-1, \ x=- \frac{ \pi }{4} + \pi k, \ uchitivaya \ ODZ: \ x=- \frac{ \pi }{4}+2 \pi k\\\\2) \ - \frac{7 \pi }{2} \leq 2\pi n \leq -2 \pi |:2\pi \\- \frac{7}{4} \leq n \leq -1, \ n=-1, \ x=-2\\[/tex]
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