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serega61356
@serega61356
August 2022
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safin1ilya
Одз
-5cosx≥0
cosx≤0
п/2+2пn≤x≤-п/2+2пn
√3tg²x-tgx=0
tgx(√3tgx-1)=0
tgx=0
x=пn,n€z
tgx=1/√3
x=п/6+пn,n€z
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Answers & Comments
-5cosx≥0
cosx≤0
п/2+2пn≤x≤-п/2+2пn
√3tg²x-tgx=0
tgx(√3tgx-1)=0
tgx=0
x=пn,n€z
tgx=1/√3
x=п/6+пn,n€z