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ageevaelena825
@ageevaelena825
July 2022
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Решите подробно пожалуйста!!!
1,6х^-1 у^12×5х^3у^-11 при х=-0,2; у=0,7
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гюйс
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1,6x^-1 y^12*5x³y^(-11)=1.6*5 x^(-1+3) y^(12+(-11))=8x²y
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1,6x^-1 y^12*5x³y^(-11)=1.6*5 x^(-1+3) y^(12+(-11))=8x²y