Решите систему уравнений. Created by marinavaulina07. algebra-ru

Объяснение:Ответ: (-8;6), (6;-8).

Решите систему уравнений...

aleksa347

Объяснение:

$\left \{ {{x+y=-2} \atop {x^2+y^2=100}} \right.\ \ \ \ \left \{ {{y=-x-2} \atop {x^2+(-x-2)^2=100}} \right. \ \ \ \ \left \{ {{y=-x-2} \atop {x^2+x^2+4x+4=100}} \right. \ \ \ \ \left \{ {{y=-x-2} \atop {2x^2+4x-96=0\ |:2}} \right. \\\left \{ {{y=-x-2} \atop {x^2+2x-48=0}} \right.\ \ \ \ \left \{ {{y=-x-2} \atop {D=196\ \ \ \ \sqrt{D}=14 }} \right. \ \ \ \ \left \{ {{y_1=6\ \ \ \ y_2=-8} \atop {x_1=-8\ \ \ \ x_2=6}} \right. .$

Ответ: (-8;6), (6;-8).

2 votes Thanks 1

sangers1959

Verified answer

Ответ:

х¹=6, у¹= -8

х²=-8 у²=6

Объяснение:

х= -2-у х=-2-у

(-2-у)²+у²=100 4+4у+у²+у²=100

2у²+4у+4=100

у²+2у+2=50

у²+2у-48=0

у¹= -8 у²=6

1 votes Thanks 1

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