РЕШИТЕ СРОЧНО
2x^2+lg10^2+F(x)=2a
где а - любое число.
F(x)=g"(х) ; g(x)=(e^x+5)(5x-3)
2x^2+lg10^2+F(x)=2a
где а - любое число.
F(x)=g"(х) ; g(x)=(e^x+5)(5x-3)
More Questions From This User See All
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
g(x)=(e^x+5)(5x-3)g'(x)=e^(x+5) (5x-3) + e^(x+5) * 5
g''(x)= e^(x+5) (5x-3) + e^(x+5) *5 + 5*e^(x+5) =e^(x+5) *(5x-3+5+5)=
=e^(x+5) * (5x+7) = F(x)
2x^2+lg10^2+F(x)=2a
2x²+2 + (5x+7) e^(x+5) =2a
x²+1 + [ (5x+7) e^(x+5) ] / 2=a