СРОЧНО!!!"""""****заранее благодарен. Created by 0Mishaj. algebra-ru

СРОЧНО!!!"""""****заранее благодарен...

0Mishaj @0Mishaj

July 2022 1 14 Report

СРОЧНО!!!"""""****заранее благодарен

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dnepr1

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1) $\lim_{x \to \infty} \frac{x^2+3x-4}{x^3-4x} = \lim_{x \to \infty} \frac{x^2}{x^3}* \frac{1+ \frac{3}{x}- \frac{1}{x^2} }{1- \frac{4}{x^2} } =[tex] \lim_{x \to \infty} \frac{1}{x} =0.$
2) $\lim_{x \to \infty} \frac{2x-3}{8x-5} = \lim_{x \to \infty} \frac{x}{x} * \frac{2- \frac{3}{x} }{8- \frac{5}{x} } = \frac{2}8} = \frac{1}{4}.$

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nuzhna pomosh pliiiz4390d4b2d069c050b8536553d51db748 53888

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Verified answer

pomogited391cb55e2eec03787d853f9f8fd2fbf 49365

nuzhna pomosh pliiiz4390d4b2d069c050b8536553d51db748 53888

9 x2v chislitele 4x3v znamenatele 9 x2 prosto ni v chisl ni v znamenatele

!!!!!!!!!!!!!!!"""""""...

pomogite pozhalujstanado srochno budu vam blagodaren

srochno ne pishite chto reshenij netoni est po teme kompleksnye chisla

ochen srochno049dfc340c81173a187da56f7cd16c5c 16095

srochno nuzhna pomosh120e163b3b196d7b5d250807714ac703 43068

pozhalujsta srochno103558e328829c13bd54f9d20b0ff023 25670

**""**"**"***:':':':...

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