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решение смотри на фотографии

[tex]\displaystyle\bf\\1)\\\\\sqrt{7-2\sqrt{6} } =\sqrt{6-2\sqrt{6} +1} =\sqrt{(\sqrt{6} )^{2}-2\sqrt{6} +1^{2} } =\\\\\\=\sqrt{(\sqrt{6} -1)^{2} } =|\sqrt{6} -1|=\sqrt{6} -1\\\\\\2)\\\\\sqrt{5-2\sqrt{6} } =\sqrt{3-2\sqrt{6} +2} =\sqrt{(\sqrt{3} )^{2}-2\sqrt{6} +(\sqrt{2}) ^{2} } =\\\\\\=\sqrt{(\sqrt{3} -\sqrt{2} )^{2} } =|\sqrt{3} -\sqrt{2} |=\sqrt{3} -\sqrt{2}[/tex]