8 - x ≥ 0 =>
x ≤ 8
x^2 - 2x - 24 = (x - 6)(x + 4)
x - 6 > 0 и x + 4 > 0
x > 6 и x > -4
или
x - 6 < 0 и x + 4 < 0
x < 6 и x < -4
x < -4 или x > 6
x < -4 или x > 6 и x ≤ 8
Ответ:
x < -4
6 < x ≤ 8
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Answers & Comments
8 - x ≥ 0 =>
x ≤ 8
x^2 - 2x - 24 = (x - 6)(x + 4)
x - 6 > 0 и x + 4 > 0
x > 6 и x > -4
или
x - 6 < 0 и x + 4 < 0
x < 6 и x < -4
x < -4 или x > 6
x < -4 или x > 6 и x ≤ 8
Ответ:
x < -4
6 < x ≤ 8