Вычислите
[tex]\displaystyle \frac{1}{1+2}+ \frac{1}{1+2 + 3} +\frac{1}{1+2 +3 + 4}+ \dots + \frac{1 }{1 + 2 + 3 + 4 +\dots+ 2023}[/tex]
Затем через n выведите общую формулу для нахождения
[tex]\displaystyle \frac{1}{1+2 }+ \frac{1}{1+2 + 3} +\frac{1}{1+2 +3 + 4}+ \dots + \frac{1 }{1 + 2 + 3 + 4 +\dots+ n }[/tex]
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