[tex]f(x)=x\sqrt{x}=x\cdot x^{1/2}=x^{1+1/2}=x^{3/2}\\f'(x)=\frac{3}{2}x^{3/2-1}=\frac{3}{2}x^{1/2}[/tex]
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[tex]f(x)=x\sqrt{x}=x\cdot x^{1/2}=x^{1+1/2}=x^{3/2}\\f'(x)=\frac{3}{2}x^{3/2-1}=\frac{3}{2}x^{1/2}[/tex]