Доведіть тотожність:
[tex] \frac{1}{9}(3y - 27) - 2( \frac{1}{12}y - 1.5) = \frac{1}{6}y [/tex]
[tex] \frac{1}{9}(3y - 27) - 2( \frac{1}{12}y - 1.5) = \frac{1}{6}y [/tex]
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