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НоВыЙ13
@НоВыЙ13
July 2022
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В треугольнике ABC угол С равен 90 градусов, [tex]tgA= \frac{ \sqrt{6} }{12} [/tex] Найдите sinA.
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Сюррикен
Cos²A=1:(1+tg²A)=1:(1+6/144)=1:150/144=144/150
sinA=√(1-cos²A)=√(1-144/150)=√(6/150)=√1/25=1/5
1 votes
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sedinalana
Verified answer
Tg a= sin a/ cos a=>
sin a= √6/?
? = √144+6= √150
sin a= √6/5√6= 1/5= 0,2.
Ответ: sin a = 0,2
2 votes
Thanks 1
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Answers & Comments
sinA=√(1-cos²A)=√(1-144/150)=√(6/150)=√1/25=1/5
Verified answer
Tg a= sin a/ cos a=>sin a= √6/?
? = √144+6= √150
sin a= √6/5√6= 1/5= 0,2.
Ответ: sin a = 0,2