Решить уравнение [tex]|x^4-x^3+x^2+5x-6|\ \textless \ x^4+x^3+x^2-5x-6[/tex]. Created by yugolovin. algebra-ru

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March 2022 1 59 Report

Решить уравнение

[tex]|x^4-x^3+x^2+5x-6|\ \textless \ x^4+x^3+x^2-5x-6[/tex]

Answers & Comments

xtoto $|T|\ \textless \ U\ \ \ \ \ \textless \ -\ \textgreater \ \ \ \ \ -U\ \textless \ T\ \textless \ U$

$|x^4-x^3+x^2+5x-6|\ \textless \ x^4+x^3+x^2-5x-6\\\\
\begin{equation*}
 \begin{cases}
 x^4-x^3+x^2+5x-6\ \textless \ x^4+x^3+x^2-5x-6 \\
 -x^4-x^3-x^2+5x+6\ \textless \ x^4-x^3+x^2+5x-6
 \end{cases}
\end{equation*}
\\\\
\begin{equation*}
 \begin{cases}
 -x^3+5x\ \textless \ x^3-5x \\
 -x^4-x^2+6\ \textless \ x^4+x^2-6
 \end{cases}
\end{equation*}
\\
\begin{equation*}
 \begin{cases}
 x^3-5x\ \textgreater \ 0 \\
 x^4+x^2-6\ \textgreater \ 0
 \end{cases}
\end{equation*}
\\
\begin{equation*}
 \begin{cases}
 x(x-\sqrt{5})(x+\sqrt{5})\ \textgreater \ 0 \\
 (x^2+3)(x^2-2)\ \textgreater \ 0
 \end{cases}
\end{equation*}
$

$\\
\begin{equation*}
 \begin{cases}
 x(x-\sqrt{5})(x+\sqrt{5})\ \textgreater \ 0 \\
 (x^2+3)(x^2-2)\ \textgreater \ 0
 \end{cases}
\end{equation*}

\\
\begin{equation*}
 \begin{cases}
 x\in(-\sqrt{5};\ 0)\cup(\sqrt{5};\ +\infty) \\
 x\in(-\infty;\ -\sqrt{2})\cup(\sqrt{2};+\infty)
 \end{cases}
\end{equation*}$

$x\in(-\sqrt{5};\ -\sqrt{2})\cup(\sqrt{5};\ +\infty)$

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Answers & Comments

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kakuyu znamenituyu italyanskuyu aktrisu kritiki nazyvali chaplinym v yubke i pochem

dokazat chto esli chetyrehugolnik yavlyaetsya odnovremenno vpisannym i opisannym

tex sostoit iz odnoj tochki

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sformulirovat i dokazat teoremu napoleona zhelatelno no ne obyazatelno dlya

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