Найдите площадь фигуры, ограниченной линиями:
[tex]y = cosx, \ \ y = ( \dfrac{2x}{ \pi } - 1)^2 [/tex]
[tex]y = cosx, \ \ y = ( \dfrac{2x}{ \pi } - 1)^2 [/tex]
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Cosx=(2x/pi-1)^2x=0 x=pi/2
S=∫pi/2,0(cosx-(2x/pi-1)^2)dx=|pi/2,0(sinx-pi(2x/pi-1)^3/6)=1-0-0-pi/6=(6-pi)/6