[tex]1+2log_{(x+2)} 5 = log_{5} (x+2)[/tex]. Created by lilinab. algebra-ru

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[tex]1+2log_{(x+2)} 5 = log_{5} (x+2)[/tex]

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$1+2log_{(x+2)} 5 = log_{5} (x+2);\\ x+2>0; x+2 \neq 1; \\ log_{x+2} 5=t \neq 0; log_5 (x+2)=\frac{1}{t} \neq 0;\\ 1+2t=\frac{1}{t};\\ t+2t^2=1;\\ 2t^2+t-1=0;\\ (2t-1)(t+1)=0;\\ t_1=0.5; t_2=-1; t=0.5$

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5^2x - 7^x -355^2x + 357^x=0...

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napishite formulu cikloparafina na sgoranie parov kotorogo rashoduetsya v 6 raz b

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5^2x - 7^x -35*5^2x + 35*7^x=0...

tex reshite pozhalujstaaa200180592268eb64aab71412664dfd79 68017

tex s obyasneniem esli mozhno

tex reshite pozhalujstaa

tex]...

tex]...

privedite ne menee treh himicheskih reakcij v rezultate kotoryh mozhet byt polu

napishite formulu cikloparafina na sgoranie parov kotorogo rashoduetsya v 6 raz b

tex reshiteeee

tex]...

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5^2x - 7^x -355^2x + 357^x=0...