Двести баллов! Решить систему уравнений, a ≠ b, b ≠ c, c ≠ a
[tex] \frac{a^{2}+2}{(a-b)(b-c)(c-a)+a} = 2a + 1[/tex]
[tex] \frac{b^{2}+2}{(a-b)(b-c)(c-a)+b} = 2b + 1[/tex]
[tex] \frac{c^{2}+2}{(a-b)(b-c)(c-a)+c} = 2c + 1[/tex]
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