Решить неравенство:
1) [tex] \frac{x^2+3x}{8}\ \textless \ \frac{x-1}{4}+ \frac{3-2x}{2} [/tex]
2) [tex] \frac{x^2-4}{x^2-9} \geq 0 [/tex]
1) [tex] \frac{x^2+3x}{8}\ \textless \ \frac{x-1}{4}+ \frac{3-2x}{2} [/tex]
2) [tex] \frac{x^2-4}{x^2-9} \geq 0 [/tex]
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