Решить неравенство:
1) [tex] \frac{x^2+3x}{8}\ \textless \ \frac{x-1}{4}+ \frac{3-2x}{2} [/tex]
2) [tex] \frac{x^2-4}{x^2-9} \geq 0 [/tex]
Please enter comments
Please enter your name.
Please enter the correct email address.
You must agree before submitting.

Answers & Comments


Copyright © 2024 SCHOLAR.TIPS - All rights reserved.