Решить уравнение:
1) [tex] \frac{1}{3x+1}- \frac{2}{3x-1}- \frac{5}{9x^2-1} = \frac{3x^2}{1-9x^2} [/tex])
2) [tex] \frac{x-2}{x+3}= \frac{x-3}{x+2} [/tex]
1) [tex] \frac{1}{3x+1}- \frac{2}{3x-1}- \frac{5}{9x^2-1} = \frac{3x^2}{1-9x^2} [/tex])
2) [tex] \frac{x-2}{x+3}= \frac{x-3}{x+2} [/tex]
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