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Неуловимыйтип
@Неуловимыйтип
June 2022
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Найдите удобную замену переменной и решите уравнение
[tex](x^2+3x-20)(x^2+3x+2)=240[/tex]
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Answers & Comments
Checov7400
Х²+3х=t х²+3х=28 х²+3х=-10
(t-20)(t+2)=240 х²+3х-28=0 х²+3х+10=0
t²+2t-20t-40=240 х1+х2=-3 х1+х2=-3
t²-18t-280=0 х1*х2=-28 х1*х2=10
t1+t2=18 х1=-7 х2=4 х1=-5 х2=2
t1*t2=280
t1=28 t2=-10
Ответ: х1=-7 х2=4 х3=-5 х4=2
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Answers & Comments
(t-20)(t+2)=240 х²+3х-28=0 х²+3х+10=0
t²+2t-20t-40=240 х1+х2=-3 х1+х2=-3
t²-18t-280=0 х1*х2=-28 х1*х2=10
t1+t2=18 х1=-7 х2=4 х1=-5 х2=2
t1*t2=280
t1=28 t2=-10
Ответ: х1=-7 х2=4 х3=-5 х4=2