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[tex] \frac{( \frac{a+1}{a-1} )^3-1+3* \frac{a+1}{a-1} -3*( \frac{a+1}{a-1} )^2}{3*( \frac{a-1}{a+1})^2- ( \frac{a-1}{a+1})^3-3( \frac{a-1}{a+1} )^3} =[/tex]
[tex] \frac{( \frac{a+1}{a-1} )^3-1+3* \frac{a+1}{a-1} -3*( \frac{a+1}{a-1} )^2}{3*( \frac{a-1}{a+1})^2- ( \frac{a-1}{a+1})^3-3( \frac{a-1}{a+1} )^3} =[/tex]
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