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danila3280
@danila3280
August 2022
1
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Тригонометрическое уравнение помогите решить пожалуйста :)
[tex]1+sinx=2cos^2x[/tex]
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Dимасuk
Verified answer
1 + sinx = 2cos²x
1 - 2cos²x + sinx = 0
2 - 2cos²x + sinx - 1 = 0
2sin²x + sinx - 1 = 0
Пусть t = sinx, t ∈ [-1; 1]
2t² + t - 1 = 0
D = 1 + 8 = 9 = 3²
t1 = (-1 + 3)/4 = 1/2
t2 = (-1 - 3)/4 = -1
Обратная замена:
sinx = 1/2
x = (-1)ⁿπ/6 + πn, n ∈ Z
sinx = -1
x = -π/2 + 2πn, n ∈ Z
2 votes
Thanks 1
danila3280
спасибо)
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Answers & Comments
Verified answer
1 + sinx = 2cos²x1 - 2cos²x + sinx = 0
2 - 2cos²x + sinx - 1 = 0
2sin²x + sinx - 1 = 0
Пусть t = sinx, t ∈ [-1; 1]
2t² + t - 1 = 0
D = 1 + 8 = 9 = 3²
t1 = (-1 + 3)/4 = 1/2
t2 = (-1 - 3)/4 = -1
Обратная замена:
sinx = 1/2
x = (-1)ⁿπ/6 + πn, n ∈ Z
sinx = -1
x = -π/2 + 2πn, n ∈ Z