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guvirmaxim1
@guvirmaxim1
July 2022
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[tex] \left \{ {{lg(x^2+y^2)=1+lg8} \atop {lg(x+y)-lg(x-y)=lg3}} \right. [/tex]
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mikael2
Lg(x²+y²)=lg10+lg8=lg80
x²+y²=80
(x+y)/(x-y)=3
x+y=3x-3y 2x=4y x=2y
4y²+y²=80 5y²=80 y²=16
y1=4 x1=8 x+y>0 x-y>0
y2=-4 x2=-8 x2+y2<0 не подходит
x=8 y=4
2 votes
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Answers & Comments
x²+y²=80
(x+y)/(x-y)=3
x+y=3x-3y 2x=4y x=2y
4y²+y²=80 5y²=80 y²=16
y1=4 x1=8 x+y>0 x-y>0
y2=-4 x2=-8 x2+y2<0 не подходит
x=8 y=4