Решить систему неравенств
[tex] \left \{ {{2^x*3^y=648} \atop {3^x*2^y=432}} \right. [/tex]
[tex] \left \{ {{2^x*3^y=648} \atop {3^x*2^y=432}} \right. [/tex]
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Перемножим оба уравнения и получим:6^х*6^у=6^7
Х+у=7
Х=7-у
Подставим во 2 уравнение
3^(7-у)*2^у=432
3^7:3^у*2^у=2^4*3^3
(2/3)^у=2^4*3^3:3^7
(2/3)^у=(2/3)^4
У=4
Х=7-4=3