Решите неравенство: [tex]1-2sin4x\ \textless \ cos^{2} 4x[/tex]. Created by НоВыЙ13. algebra-ru

1-2sin4x<1-sin²4xsin²4x-2sin4x<0sin4x(sin4x-2)<01{sin4x<0⇒π+2πk<4x<2π+2πk⇒π/4+πk/2<x<π/2+πk/2{sin4x>2 нет решения2sin4x>0⇒2πk<4x<π+2πk⇒πk/2<x<π/4+πk/2{sin4x<2⇒x∈Rx∈(πk/2;π/4+πk/2,k∈z)Новые вопросы в Алгебра9. При яких значеннях і функція f(x) = x³ - 3bх² + 12x + 1 зростає на R?Помогоите Срочно!!!!!!Помогите не понимаю как решить Срочно!!!!!!!!!СРОЧНО, ЗАРАНИЕ СПАСИБО ЗА ПОМОЩ!!!!Укажіть головний період функції y=5tg(x/8 + π/6)ДАЮ 50 БАЛЛОВ!!!!!!!ДАЮ 50 БАЛЛОВ!!!!!!!!ДАЮ 50 БАЛЛОВ! УпроститьДАЮ 50 БАЛЛОВ! Найти косинусребята помогите пожалуйста решить задачузнайдіть tg a якщо sin a 4/5 і п/2 <а < пПредыдущийСледующийВместе мы знаем большеЭтот сайт использует cookies Политика Cookies . 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tex]...

НоВыЙ13 @НоВыЙ13

June 2022 1 8 Report

Решите неравенство:
[tex]1-2sin4x\ \textless \ cos^{2} 4x[/tex]

Answers & Comments

sedinalana 1-2sin4x<1-sin²4x
sin²4x-2sin4x<0
sin4x(sin4x-2)<0
1
{sin4x<0⇒π+2πk<4x<2π+2πk⇒π/4+πk/2<x<π/2+πk/2
{sin4x>2 нет решения
2
sin4x>0⇒2πk<4x<π+2πk⇒πk/2<x<π/4+πk/2
{sin4x<2⇒x∈R
x∈(πk/2;π/4+πk/2,k∈z)