Home
О нас
Products
Services
Регистрация
Войти
Поиск
НоВыЙ13
@НоВыЙ13
July 2022
2
13
Report
Решите уравнение:
[tex]2log_{2}(1- \frac{13}{2x+7} )=3log_{2}(2+ \frac{13}{x-3} )+2[/tex]
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
contrlc
Verified answer
Ответ::::::::::::::::::::
3 votes
Thanks 1
sedinalana
Verified answer
1-13/(2x+7)=(2x+7-13)/(2x+7)=(2x-6)/(2x+7)=2(x-3)/(2x+7)
2+13/(x-3)=(2x-6+13)/(x-3)=(2x+7)/(x-3)
--------------------------------
2log(2)[2(x-3)/(2x+7)]=3log(2)[(2x+7)/(x-3)]+2
ОДз
(x-3)/(2x+7)>0
x=3 x=-3,5
x∈(-∞;-3,5) U (3;∞)
log(2)[2(x-3)/(2x+7)]²=log(2)[4(2x+7)³/(x-3)]
4(x-3)²/(2x+7)²=4(2x+7)³/(x-3)³
(x-3)²/(2x+7)²=(2x+7)³/(x-3)³
(x-3)^5=(2x+7)^5
x-3=2x+7
2x-x=-3-7
x=-10
0 votes
Thanks 0
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "tex]..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
Ответ::::::::::::::::::::Verified answer
1-13/(2x+7)=(2x+7-13)/(2x+7)=(2x-6)/(2x+7)=2(x-3)/(2x+7)2+13/(x-3)=(2x-6+13)/(x-3)=(2x+7)/(x-3)
--------------------------------
2log(2)[2(x-3)/(2x+7)]=3log(2)[(2x+7)/(x-3)]+2
ОДз
(x-3)/(2x+7)>0
x=3 x=-3,5
x∈(-∞;-3,5) U (3;∞)
log(2)[2(x-3)/(2x+7)]²=log(2)[4(2x+7)³/(x-3)]
4(x-3)²/(2x+7)²=4(2x+7)³/(x-3)³
(x-3)²/(2x+7)²=(2x+7)³/(x-3)³
(x-3)^5=(2x+7)^5
x-3=2x+7
2x-x=-3-7
x=-10