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guvirmaxim1
@guvirmaxim1
July 2022
2
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[tex] 25^{x} +4*5^x-5=0[/tex]
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Алкадиеныч
Verified answer
Пусть 5^x=t t>0
t^2+4t-5=0
t1=-5
t2=1
ПО ОДЗ подходит корень 1
t=1
5^x=1
x=0
Ответ x=0
2 votes
Thanks 2
sangers1959
Verified answer
25ˣ+4*5ˣ-5=0
5²ˣ+4*5ˣ-5=0
Пусть 5ˣ=t>0
t²+4t-5=0 D=36
t₁=-5 ∉
t₂=1 ⇒
5ˣ=1
x=0.
Ответ: х=0.
2 votes
Thanks 1
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Answers & Comments
Verified answer
Пусть 5^x=t t>0t^2+4t-5=0
t1=-5
t2=1
ПО ОДЗ подходит корень 1
t=1
5^x=1
x=0
Ответ x=0
Verified answer
25ˣ+4*5ˣ-5=05²ˣ+4*5ˣ-5=0
Пусть 5ˣ=t>0
t²+4t-5=0 D=36
t₁=-5 ∉
t₂=1 ⇒
5ˣ=1
x=0.
Ответ: х=0.