[tex] \frac{x-1}{x+3} \ \textgreater \ 2[/tex]. Created by НоВыЙ13. algebra-ru

метод интервалов:1. 2. - + - -------(-7)----------(-3)-------------->x3. ответ: x∈(-7;-3)

tex]...

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[tex] \frac{x-1}{x+3} \ \textgreater \ 2[/tex]

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kirichekov

Verified answer

$\frac{x-1}{x+3} \ \textgreater \ 2$
$\frac{x-1}{x+3} -2\ \textgreater \ 0$
$\frac{x-1-2*(x+3)}{x+3}\ \textgreater \ 0$
$\frac{-x-7}{x+3} \ \textgreater \ 0$ метод интервалов:
1. $\frac{-x-7}{x+3} =0

 \left \{ {{x=-7} \atop {x} \neq -3} \right. 

$
2.
- + -
-------(-7)----------(-3)-------------->x

3. ответ: x∈(-7;-3)

2 votes Thanks 1

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