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НоВыЙ13
@НоВыЙ13
November 2021
2
15
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Сравнить числа:
[tex]( \sqrt{5} + \sqrt{10})^{2} [/tex] и [tex]14+ \sqrt{200} [/tex]
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gksoso
Решение во вложении :)
1 votes
Thanks 1
НоВыЙ13
sqrt это корень?
gksoso
да
koingrel
Verified answer
(sqrt5+sqrt10)²= 5+2*sqrt5*sqrt10+10= 15+25sqrt2
14+sqrt200=14+ 10sqrt2
(sqrt5+sqrt10)²> 14+sqrt200
2 votes
Thanks 1
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Answers & Comments
Verified answer
(sqrt5+sqrt10)²= 5+2*sqrt5*sqrt10+10= 15+25sqrt214+sqrt200=14+ 10sqrt2
(sqrt5+sqrt10)²> 14+sqrt200