помогите пожалуйста [tex]log_{5}(x+1)+ log_5(x-3)=1 [/tex]. Created by leratrifonova1. algebra-ru

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leratrifonova1 @leratrifonova1

August 2022 1 8 Report

помогите пожалуйста [tex]log_{5}(x+1)+ log_5(x-3)=1 [/tex]

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ShirokovP

Verified answer

ОДЗ
x > 3

(x + 1)(x - 3) = 5
x^2 - 2x - 3 - 5= 0
x^2 - 2x - 8 = 0
D = 4 + 4*8 = 36
x1 = ( 2 + 6)/2 = 8/2 = 4 ∈ ОДЗ
x2 = ( 2 - 6)/2 = - 4/2 = - 2 ∉ ОДЗ

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leratrifonova1 August 2022 | 0 Ответы

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leratrifonova1 August 2022 | 0 Ответы

na kartochkah vypisany celye chisla ot 1 do 12 vklyuchitelno naudachu vybirayutsya dv

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leratrifonova1 August 2022 | 0 Ответы

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na kartochkah vypisany celye chisla ot 1 do 12 vklyuchitelno naudachu vybirayutsya dv

zadachapomogite pozhalujsta hotya by 1 2och proshu

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pomogite pozhalujsta hot chto nibud sdelat ot 3 do 23 chto nibud iz nih

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