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babakin
@babakin
July 2022
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[tex]8 \sqrt{3} sinx-8cosx+ \sqrt{3}sin2x-cos2x=1 \left[\begin{array}{ccc} -\pi; \frac{ \pi }{3} \end{array}\right] [/tex]
Решить уравнение и найти корни на заданном промежутке.
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