[tex]8 \sqrt{3} sinx-8cosx+ \sqrt{3}sin2x-cos2x=1 \left[\begin{array}{ccc} -\pi; \frac{ \pi }{3} \end{array}\right] [/tex]
Решить уравнение и найти корни на заданном промежутке.
Please enter comments
Please enter your name.
Please enter the correct email address.
You must agree before submitting.

Copyright © 2024 SCHOLAR.TIPS - All rights reserved.