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novokuznetsk
@novokuznetsk
July 2022
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умоляю найдите производную y=log x по основанию (х+1)
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sedinalana
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Y=log(x+1)x=lnx/ln(x+1)
y`=[ln(x+1)/x-lnx/(x+1)]/ln²(x+1)=ln(x+1)/[xln²(x+1)]-lnx/[(x+1)ln²(x+1)]=
=1/[xln(x+1)]-lnx/(x+1)ln²(x+1)]
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Answers & Comments
Verified answer
Y=log(x+1)x=lnx/ln(x+1)y`=[ln(x+1)/x-lnx/(x+1)]/ln²(x+1)=ln(x+1)/[xln²(x+1)]-lnx/[(x+1)ln²(x+1)]=
=1/[xln(x+1)]-lnx/(x+1)ln²(x+1)]