a=log5 20=1+log5 4=1+2log5 2=1+2/log2 5
б=log40 128=7log40 2=7/(3+log2 5)
log2 5=7/б-3
a=1+2/7/(б-3)-1+2(б-3)/7
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a=log5 20=1+log5 4=1+2log5 2=1+2/log2 5
б=log40 128=7log40 2=7/(3+log2 5)
log2 5=7/б-3
a=1+2/7/(б-3)-1+2(б-3)/7