Ответ:
[tex] {(x + 1)}^{2} > x(x + 2) \\ {x}^{2} + 2x + 1 > {x}^{2} + 2x \\ 1 > 0[/tex]
верно
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
Ответ:
[tex] {(x + 1)}^{2} > x(x + 2) \\ {x}^{2} + 2x + 1 > {x}^{2} + 2x \\ 1 > 0[/tex]
верно