Verified answer

Ответ:

на фото

Объяснение:

[tex]\displaystyle\bf\\1)\\\\\frac{b}{b^{2}-8b+16 } -\frac{b+6}{b^{2} -16} =\frac{b}{b^{2}-2\cdot b\cdot 4+4^{2} } -\frac{b+6}{b^{2}-4^{2} } =\\\\\\=\frac{b}{(b-4)^{2} } -\frac{b+6}{(b-4)\cdot(b+4)}=\frac{b\cdot(b+4)-(b+6)\cdot(b-4)}{(b-4)^{2}\cdot(b+4) } =\\\\\\=\frac{b^{2}+4b-b^{2} +4b-6b+24 }{(b-4)^{2} \cdot(b+4)} =\frac{2b+24}{(b-4)^{2} \cdot(b+4)} =\frac{2\cdot(b+12)}{(b-4)^{2} \cdot(b+4)} \\\\2)[/tex]

[tex]\displaystyle\bf\\\frac{2\cdot(b+12)}{(b-4)^{2} \cdot(b+4)} :\frac{b+12}{b^{2} -16} =\frac{2\cdot(b+12)}{(b-4)^{2} \cdot(b+4)} \cdot\frac{(b-4)\cdot(b+4)}{b+12} =\\\\\\=\frac{2}{b-4} \\\\\\\frac{2}{b-4} =\frac{2}{b-4}[/tex]

Тождество доказано