December 2021 0 16 Report
1) (sinx-1)tgx-3sinx+3=0 (метод: розкладання на множники; в-дь:arctg3+πn,nєZ); 2) (1-cos6x)cos20x=sin^2(3x) (метод: розкладання на множники; в-дь: πn/3; (+;-)π/60+πm/10, n,mєZ).
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