Ответ:
-1; -2
Пошаговое объяснение:
[tex]log_5(1-6x-2x^2)=lg10\\\\OD3:1-6x-2x^2 > 0\\\\\\log_5(1-6x-2x^2)=1\\\\log_5(1-6x-2x^2)=log_55\\\\1-6x-2x^2=5\\\\2x^2+6x+4=0\; |:2\\\\x^2+3x+2=0\\\\\left \{ {{x_1*x_2=2} \atop {x_1+x_2=-3}} \right.= > x_1=-1;x_2=-2\\\\1-6x-2x^2 > 0\\\\x_1=-1\; \;\; \;\; \; 1-6(-1)-2(-1)^2=1+6-2=5 > 0\\x_2=-2\; \; \; \; \; \; 1-6(-2)-2(-2)^2=1+12-8=5 > 0\\\\x_1=-1;x_2=-2[/tex]
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Answers & Comments
Ответ:
-1; -2
Пошаговое объяснение:
[tex]log_5(1-6x-2x^2)=lg10\\\\OD3:1-6x-2x^2 > 0\\\\\\log_5(1-6x-2x^2)=1\\\\log_5(1-6x-2x^2)=log_55\\\\1-6x-2x^2=5\\\\2x^2+6x+4=0\; |:2\\\\x^2+3x+2=0\\\\\left \{ {{x_1*x_2=2} \atop {x_1+x_2=-3}} \right.= > x_1=-1;x_2=-2\\\\1-6x-2x^2 > 0\\\\x_1=-1\; \;\; \;\; \; 1-6(-1)-2(-1)^2=1+6-2=5 > 0\\x_2=-2\; \; \; \; \; \; 1-6(-2)-2(-2)^2=1+12-8=5 > 0\\\\x_1=-1;x_2=-2[/tex]