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veffi
@veffi
August 2022
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Найти область значений функции
y=(x^2 +9)/2x
Заранее спасибо
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Единорожек34
Y=(x²+9)/2x
2xy=x²+9
x²-2yx+9=0
D/4=y²-9 ≥ 0
(y-3)(y+3) ≥ 0
y∈(-∞;-3]∪[3;∞)
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Answers & Comments
2xy=x²+9
x²-2yx+9=0
D/4=y²-9 ≥ 0
(y-3)(y+3) ≥ 0
y∈(-∞;-3]∪[3;∞)