August 2022 1 10 Report
[tex] \frac{2}{x}=\frac{\sqrt{5-4x}}{x^{2}}+\frac{1}{\sqrt{5-4x }} [/tex]
[tex] \frac{2 }{x } =5-4x +x^{2} [/tex]
[tex] 2=5x-4x^{2}+x^{3}
[/tex]
[tex] x^{3 } - 4x^{2} +5x-2=0 [/tex]
Правильно ли начато? Как дорешать?
Please enter comments
Please enter your name.
Please enter the correct email address.
You must agree before submitting.

Answers & Comments


Copyright © 2024 SCHOLAR.TIPS - All rights reserved.