August 2022 1 9 Report
[tex] \frac{2}{x}=\frac{\sqrt{5-4x}}{x^{2}}+\frac{1}{\sqrt{5-4x }} [/tex]
[tex] \frac{2 }{x } =5-4x +x^{2} [/tex]
[tex] 2=5x-4x^{2}+x^{3}
[/tex]
[tex] x^{3 } - 4x^{2} +5x-2=0 [/tex]
Правильно ли начато? Как дорешать?
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