81^ log3 5 +27^log9 36 + 3^4log 9 7. Created by Nurzhan94. algebra-ru

81^ log3 5 +27^log9 36 + 3^4log 9 7...

July 2022 2 19 Report

81^ log3 5 +27^log9 36 + 3^4log 9 7

MizoriesKun

$81^{log_{3}5}+ 27^{log_{9}36}+ 3^{4log_{9}7}=( 3^{log_{3}5}) ^{4}+( 3^{log_{3}6}) ^{3}+( 3^{log_{3}\sqrt{7}}) ^{4}= 5^{4}+ 6^{3}+( \sqrt{7}) ^{4}=625+216+49=890$

1 votes Thanks 1

Universalka

Verified answer

81^ log3 5 +27^log9 36 + 3^4log 9 7=

3^ 4log3 5 +3^3log3 √36 +

+ 3^4log3 √ 7 =

3^ log3 5^4 +3^log3 6^3+ 3^log3 7^2=

= 5^4+ 6^3 +7^2 = 890

7 votes Thanks 1

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