a=10, b=3, ∠(a;b)=∠C
sinC =0,8 => cosC =±√(1-sin^2) =±0.6
Теорема косинусов
с^2 =a^2 +b^2 -2ab cosC
c^2 =100+9 ±60*3/5 =109±36
c ={√73; √145}
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
a=10, b=3, ∠(a;b)=∠C
sinC =0,8 => cosC =±√(1-sin^2) =±0.6
Теорема косинусов
с^2 =a^2 +b^2 -2ab cosC
c^2 =100+9 ±60*3/5 =109±36
c ={√73; √145}