Ответ:

[tex]1) log_{5} 6 = log_{5} (2 \times 3) = log_{5} 2 + log_{5} 3 = a + b \\ 2)log_{5} 10 = log_{5} (2 \times 5) = log_{5} 2 + log_{5} 5 = a + 1 \\ 3)log_{5} 18 = log_{5} (2 \times {3}^{2} ) = log_{5} 2 + log_{5} {3}^{2} = log_{5} 2 + 2log_{5} 3 = a + 2b \\ 4)log_{3} 2 = \frac{log_{5} 2}{log_{5} 3} = \frac{a}{b} [/tex]