Ответ: t = (pi - V(pi^2+16)) / 4
Объяснение: по условию
-pi/2 <= t <= pi/2
2t^2 - pi*t - 2 = 0
D=pi^2+16
t1 = (pi - V(pi^2+16)) / 4
t2 = (pi + V(pi^2+16)) / 4 > pi/2
t2 примерно= (3.14+5.1)/4 > 1.57
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Ответ: t = (pi - V(pi^2+16)) / 4
Объяснение: по условию
-pi/2 <= t <= pi/2
2t^2 - pi*t - 2 = 0
D=pi^2+16
t1 = (pi - V(pi^2+16)) / 4
t2 = (pi + V(pi^2+16)) / 4 > pi/2
t2 примерно= (3.14+5.1)/4 > 1.57